2019 question paper

Discrete Mathematics

13 questions

  1. Q1a. The statement p → q is logically equivalent to (i) p ∨ q (ii) p ∨ ~q (iii) ~p ∨ q (iv) ~p → q20192m

    Module 3: Propositional Logic & Proof Techniques.

    The statement p → q is logically equivalent to
    (i) p ∨ q
    (ii) p ∨ ~q
    (iii) ~p ∨ q
    (iv) ~p → q

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  2. Q1b. The contrapositive of the conditional statement p \rightarrow q is (i) q \rightarrow p (ii) \sim p \rightarrow \sim q (iii) p \rightarrow q (iv) \sim q \rightarrow \sim p20192m

    Module 3: Propositional Logic & Proof Techniques.

    The contrapositive of the conditional statement p→qp \rightarrow q is
    (i) q→pq \rightarrow p
    (ii) ∼p→∼q\sim p \rightarrow \sim q
    (iii) p→qp \rightarrow q
    (iv) ∼q→∼p\sim q \rightarrow \sim p

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  3. Q1c. If A and B are two nonempty sets having n elements in common, then A \times B and B \times A will have how many elements in common? (i) 2^n (ii) n^2 (iii) n^4 (iv) 2n20192m

    Module 1: Sets, Relation and Function.

    If AA and BB are two nonempty sets having nn elements in common, then A×BA \times B and B×AB \times A will have how many elements in common?
    (i) 2n2^n
    (ii) n2n^2
    (iii) n4n^4
    (iv) 2n2n

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  4. Q1d. If a set A have n elements, then how many relations will be there on set A? (i) n^2 (ii) 2^(n^2) (iii) 2^n (iv) 2n20192m

    Module 1: Sets, Relation and Function.

    If a set A have n elements, then how many relations will be there on set A?
    (i) n^2
    (ii) 2^(n^2)
    (iii) 2^n
    (iv) 2n

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  5. Q1e. (e) If P(Φ) represents the power set of Φ, then n(P(P(P(Φ)))) equal to (i) 1 (ii) 2 (iii) 3 (iv) 420192m

    Module 1: Sets, Relation and Function.

    (e) If P(Φ) represents the power set of Φ, then n(P(P(P(Φ)))) equal to
    (i) 1
    (ii) 2
    (iii) 3
    (iv) 4

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  6. Q1f. (f) For the poset [{3, 5, 9, 15, 24, 45}]; divisor of | the bus of {3, 5} is (i) 3 (ii) 5 (iii) 15 (iv) 4520192m

    Module 1: Sets, Relation and Function.

    (f) For the poset [{3, 5, 9, 15, 24, 45}]; divisor of | the bus of {3, 5} is
    (i) 3
    (ii) 5
    (iii) 15
    (iv) 45

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  7. Q1g. (g) If (S, *) is a monoid, where S = {1, 2, 3, 6} and * is defined by a * b = lcm(a, b), where a, b ∈ S, then the identity element is (i) 1 (ii) 2 (iii) 3 (iv) 620192m

    Module 1: Sets, Relation and Function.

    (g) If (S, *) is a monoid, where S = {1, 2, 3, 6} and * is defined by a * b = lcm(a, b), where a, b ∈ S, then the identity element is
    (i) 1
    (ii) 2
    (iii) 3
    (iv) 6

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  8. Q1h. (h) The total number of subgroups of group G of prime order is (i) 1 (ii) 2 (iii) 3 (iv) 420192m

    Module 1: Sets, Relation and Function.

    (h) The total number of subgroups of group G of prime order is
    (i) 1
    (ii) 2
    (iii) 3
    (iv) 4

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  9. Q1i. (i) The number of edges in a bipartite graph with n vertices is at most (i) n^2/2 (ii) n^2/4 (iii) n^2 (iv) 2n20192m

    Module 1: Sets, Relation and Function.

    (i) The number of edges in a bipartite graph with n vertices is at most (i) n^2/2 (ii) n^2/4 (iii) n^2 (iv) 2n

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  10. Q2a. Using truth table, show that- (i) ((p → (q → r)) → ((p → q) → (p → r))) is a tautology; (ii) ¬(q → r) ∧ r ∧ (p → q) is a contradiction.201914m

    Module 3: Propositional Logic & Proof Techniques.

    Using truth table, show that-
    (i) ((p → (q → r)) → ((p → q) → (p → r))) is a tautology;
    (ii) ¬(q → r) ∧ r ∧ (p → q) is a contradiction.

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  12. Q2b. Obtain the principal disjunctive normal form (PDNF) and principal conjunctive normal form (PCNF) of the statement (p → (q ∧ r)) ∧ (¬p → (¬q ∧ ¬r)).201914m

    Module 3: Propositional Logic & Proof Techniques.

    Obtain the principal disjunctive normal form (PDNF) and principal conjunctive normal form (PCNF) of the statement
    (p → (q ∧ r)) ∧ (¬p → (¬q ∧ ¬r)).

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  13. Q3a. For any sets A and B, prove that (i) (A ∪ B)' = A' ∩ B' (ii) (A ∩ B)' = A' ∪ B'201914m

    Module 1: Sets, Relation and Function.

    For any sets A and B, prove that
    (i) (A ∪ B)' = A' ∩ B'
    (ii) (A ∩ B)' = A' ∪ B'

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  14. Q3b. If two sets A and B have n elements in common, then show that the sets A × B and B × A will have 2^n elements in common.20197m

    Module 1: Sets, Relation and Function.

    If two sets A and B have n elements in common, then show that the sets A × B and B × A will have 2^n elements in common.

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