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Discrete MathematicsUsing truth table, show that- (i) ((p → (q → r)) → ((p → q) → (p → r))) is a tautology; (ii) ¬(q → r) ∧ r ∧ (p → q) is a contradiction.201914mDiscrete MathematicsObtain the principal disjunctive normal form (PDNF) and principal conjunctive normal form (PCNF) of the statement (p → (q ∧ r)) ∧ (¬p → (¬q ∧ ¬r)).201914mDiscrete MathematicsThe statement (\sim P \leftrightarrow Q) \land \sim Q is true, when (i) P : True, Q : False (ii) P : True, Q : True (iii) P : False, Q : True (iv) P : False, Q : False20222mDiscrete MathematicsThe statement p → q is logically equivalent to (i) p ∨ q (ii) p ∨ ~q (iii) ~p ∨ q (iv) ~p → q20192m