Use the pumping lemma to prove that the language L = \{a^n b^n : n \ge — PYQDeck

PyQdeckBEU PYQ Archive Subjects

Back to the 2025 paper

Module 1: Introduction & Regular Languages

20257m

Use the pumping lemma to prove that the language $L = \{a^n b^n : n \ge 1\}$ is not regular.

Search Google Ask AI

Similar questions

FORMAL LANGUAGE & AUTOMATA THEORYShow that the language: L = \{ a^{n^2} b^n \mid n \ge 0 \} is not regular.20227m Formal Language & Automata TheoryUsing Pumping Lemma, prove that the language L = \{0^{n}1^{n} \mid n \ge 0\} is not regular.20257m FORMAL LANGUAGE & AUTOMATA THEORYProve that L = \{ a^i b^i \mid i \ge 0 \} is not regular using the pumping lemma.20247m Formal Language & Automata TheoryProve using pumping lemma for regular languages that the language \{ 0^n / n \text{ is a perfect square} \} is not regular.20227m

PreviousGiven a DFA D over the alphabet {a, b}, perform DFA minimization and draw the equivalent minimal DFA accepting the same language. ![image](https://res.cloudinary.com/djkpavwmp/image/upload/v1766402014/portfolio_assets/ixqepvuicnt6ji19qb3o.png)NextShow that the following grammar is ambiguous: S \rightarrow SS | aSb | bSa | \epsilon