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Data MiningBuild a decision tree using the training data in the table given below. Divide the height attribute into ranges as follows: [0, 1.6], \quad [1.6, 1.7], \quad [1.7, 1.8], \quad [1.8, 1.9], \quad [1.9, 2.0], \quad [2.0, 5.0] | Gender | Height (m) | Class | | :---: | :---: | :---: | | F | 1.6 | Short | | M | 2 | Tall | | F | 1.9 | Medium | | F | 1.88 | Medium | | F | 1.7 | Short | | M | 1.85 | Medium | | F | 1.6 | Short | | M | 1.7 | Short | | M | 2.2 | Tall | | M | 2.1 | Tall | | F | 1.8 | Medium | | M | 1.95 | Medium | | F | 1.9 | Medium | | F | 1.8 | Medium | | F | 1.75 | Medium |20237mMACHINE LEARNINGFor the Sun Burn data set given below, construct a decision tree. | Name | Hair | Height | Weight | Location | Class | |--------|--------|----------|---------|----------|-------| | Sunita | Blonde | Average | Light | No | Yes | | Anita | Blonde | Tall | Average | Yes | No | | Kavita | Brown | Short | Average | Yes | No | | Sushma | Blonde | Short | Average | No | Yes | | Xavier | Red | Average | Heavy | No | Yes | | Balaji | Brown | Tall | Heavy | No | No | | Ramesh | Brown | Average | Heavy | No | No | | Sweta | Blonde | Short | Light | Yes | No |202314mMACHINE LEARNINGApply the ID3 algorithm on the following data to draw a decision tree. Show the Information Gain at each split. ### Dataset | Outlook | Temperature | Humidity | Windy | PlayTennis | |-----------|-------------|----------|-------|-------------| | Sunny | Hot | High | False | No | | Sunny | Hot | High | True | No | | Overcast | Hot | High | False | Yes | | Rainy | Mild | High | False | Yes | | Rainy | Cool | Normal | False | Yes | | Rainy | Cool | Normal | True | No | | Overcast | Cool | Normal | True | Yes | | Sunny | Mild | High | False | No | | Sunny | Cool | Normal | False | Yes | | Rainy | Mild | Normal | False | Yes | | Sunny | Mild | Normal | True | Yes | | Overcast | Mild | High | True | Yes | | Overcast | Hot | Normal | False | Yes | | Rainy | Mild | High | True | No |202510mData MiningDraw decision tree for the following data sets. Use entropy as a node selection mechanism: | Outlook | Temp (F) | Humidity | Windy | Class | |:---|:---|:---|:---|:---| | Rainy | Hot | High | False | No | | Rainy | Hot | High | True | No | | Overcast | Hot | High | False | Yes | | Sunny | Mild | High | False | Yes | | Sunny | Cool | Normal | False | Yes | | Sunny | Cool | Normal | True | No | | Overcast | Cool | Normal | True | Yes | | Rainy | Mild | High | False | No | | Rainy | Cool | Normal | False | Yes | | Sunny | Mild | Normal | False | Yes | | Rainy | Mild | Normal | True | Yes | | Overcast | Mild | High | True | Yes | | Overcast | Hot | Normal | False | Yes | | Sunny | Mild | High | True | No |202014m
PreviousFor the following vectors, x and y, calculate the indicated similarity or distance measures : \mathbf{x} = \{0, 1, 0, 1\}, \quad \mathbf{y} = \{1, 0, 1, 0\} Calculate: 1. Cosine similarity 2. Correlation 3. Euclidean distance 4. Jaccard similarityNextWhat is over-fitting and under-fitting of a model? When do they happen?
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