Using super and constructor order

super(...) invokes a superclass constructor and must be the first statement in a constructor. super.method() calls an accessible superclass method implementation.

class Person {
    Person(String name) { System.out.println("Person: " + name); }
    void info() { System.out.println("Person info"); }
}
class Student extends Person {
    Student(String name) {
        super(name);
        System.out.println("Student created");
    }
    @Override void info() {
        super.info();
        System.out.println("Student info");
    }
}
class Demo {
    public static void main(String[] args) {
        Student s = new Student("Asha");
        s.info();
    }
}

Output order: Person: Asha, Student created, then Person info, Student info. The superclass constructor runs before the subclass constructor body.