Discrete Mathematics

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Module 3: Propositional Logic & Proof Techniques.

  1. 1a. The statement (\sim P \leftrightarrow Q) \land \sim Q is true, when (i) P : True, Q : False (ii) P : True, Q : True (iii) P : False, Q : True (iv) P : False, Q : False20222m

    Module 3: Propositional Logic & Proof Techniques.

    The statement (∼P↔Q)∧∼Q(\sim P \leftrightarrow Q) \land \sim Q is true, when

    (i) PP : True, QQ : False
    (ii) PP : True, QQ : True
    (iii) PP : False, QQ : True
    (iv) PP : False, QQ : False

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    Worked Solution

    Answer

    Correct Option: (i) PP: True, QQ: False

    Explanation

    Given statement: (∼P↔Q)∧∼Q(\sim P \leftrightarrow Q) \land \sim Q

    For the conjunction to be true, both parts must be true:

    1. ∼Q\sim Q is true   ⟹  Q=False\implies Q = \text{False}
    2. (∼P↔Q)(\sim P \leftrightarrow Q) must be true with Q=FalseQ = \text{False}

    Biconditional truth condition

    A↔BA \leftrightarrow B is true iff AA and BB have same truth value.

    So with Q=FalseQ = \text{False}:
    ∼P↔Q=True  ⟹  ∼P=Q=False  ⟹  P=True\sim P \leftrightarrow Q = \text{True} \implies \sim P = Q = \text{False} \implies P = \text{True}

    Verification via Truth Table

    PP QQ ∼P\sim P ∼P↔Q\sim P \leftrightarrow Q ∼Q\sim Q (∼P↔Q)∧∼Q(\sim P \leftrightarrow Q) \land \sim Q
    T T F F F F
    T F F T T T
    F T T T F F
    F F T F T F

    Only row P=T,Q=FP=T, Q=F yields true.

    Final Answer

    The statement is true exactly when PP is True and QQ is False, i.e., option (i).

  2. 3a. (a) Prove the following: (i) There is a real number x such that x > 1 and 2^x > x^{10}. (ii) There is an integer n such that 2n^2 - 5n + 2 is prime.202210m

    Module 3: Propositional Logic & Proof Techniques.

    (a) Prove the following:

    (i) There is a real number xx such that x>1x > 1 and 2x>x102^x > x^{10}.
    (ii) There is an integer nn such that 2n2−5n+22n^2 - 5n + 2 is prime.

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  3. 3b. Disprove that for all real numbers a and b, if a < b, then a^2 < b^2.20224m

    Module 3: Propositional Logic & Proof Techniques.

    Disprove that for all real numbers aa and bb, if a<ba < b, then a2<b2a^2 < b^2.

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  4. 4a. (a) Show that p \lor (q \land r) and (p \lor q) \land (p \lor r) are logically equivalent. This is the distributive law of disjunction over conjunction.20225m

    Module 3: Propositional Logic & Proof Techniques.

    (a) Show that p∨(q∧r)p \lor (q \land r) and (p∨q)∧(p∨r)(p \lor q) \land (p \lor r) are logically equivalent. This is the distributive law of disjunction over conjunction.

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  5. 5b. Write short notes on the following: (i) Forward proof (ii) Disjunctive and conjunctive normal form (iii) Fundamental theorem of arithmetic This question covers topics from different modules: * (i) Forward proof: This falls under Module 3: Propositional Logic & Proof Techniques. * (ii) Disjunctive and conjunctive normal form: This also falls under Module 3: Propositional Logic & Proof Techniques, as these are concepts in propositional logic. * (iii) Fundamental theorem of arithmetic: This is a concept from number theory, which is typically covered in Module 2: Mathematical Induction & Counting Techniques (as number theory is often grouped with induction and counting in discrete mathematics courses).20227m

    Module 3: Propositional Logic & Proof Techniques.

    Write short notes on the following:

    (i) Forward proof
    (ii) Disjunctive and conjunctive normal form
    (iii) Fundamental theorem of arithmetic

    This question covers topics from different modules:

    • (i) Forward proof: This falls under Module 3: Propositional Logic & Proof Techniques.
    • (ii) Disjunctive and conjunctive normal form: This also falls under Module 3: Propositional Logic & Proof Techniques, as these are concepts in propositional logic.
    • (iii) Fundamental theorem of arithmetic: This is a concept from number theory, which is typically covered in Module 2: Mathematical Induction & Counting Techniques (as number theory is often grouped with induction and counting in discrete mathematics courses).
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  6. 7a. Check the validity of the following argument all integers are rational numbers. Some integers are powers of 5. There fore, some rational numbers are powers of 520237m

    Module 3: Propositional Logic & Proof Techniques.

    Check the validity of the following argument all integers are rational numbers. Some integers are

    powers of 5. There fore, some rational numbers are powers of 5

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  7. Q1a. The statement p → q is logically equivalent to (i) p ∨ q (ii) p ∨ ~q (iii) ~p ∨ q (iv) ~p → q20192m

    Module 3: Propositional Logic & Proof Techniques.

    The statement p → q is logically equivalent to
    (i) p ∨ q
    (ii) p ∨ ~q
    (iii) ~p ∨ q
    (iv) ~p → q

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  8. Q1b. The contrapositive of the conditional statement p \rightarrow q is (i) q \rightarrow p (ii) \sim p \rightarrow \sim q (iii) p \rightarrow q (iv) \sim q \rightarrow \sim p20192m

    Module 3: Propositional Logic & Proof Techniques.

    The contrapositive of the conditional statement p→qp \rightarrow q is
    (i) q→pq \rightarrow p
    (ii) ∼p→∼q\sim p \rightarrow \sim q
    (iii) p→qp \rightarrow q
    (iv) ∼q→∼p\sim q \rightarrow \sim p

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  9. Q2a. Using truth table, show that- (i) ((p → (q → r)) → ((p → q) → (p → r))) is a tautology; (ii) ¬(q → r) ∧ r ∧ (p → q) is a contradiction.201914m

    Module 3: Propositional Logic & Proof Techniques.

    Using truth table, show that-
    (i) ((p → (q → r)) → ((p → q) → (p → r))) is a tautology;
    (ii) ¬(q → r) ∧ r ∧ (p → q) is a contradiction.

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  10. Q2b. Obtain the principal disjunctive normal form (PDNF) and principal conjunctive normal form (PCNF) of the statement (p → (q ∧ r)) ∧ (¬p → (¬q ∧ ¬r)).201914m

    Module 3: Propositional Logic & Proof Techniques.

    Obtain the principal disjunctive normal form (PDNF) and principal conjunctive normal form (PCNF) of the statement
    (p → (q ∧ r)) ∧ (¬p → (¬q ∧ ¬r)).

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