Using Pumping Lemma for CFLs, prove that L = \{a^{n}b^{n}c^{n} \mid n — PYQDeck

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Module 2: Context-free languages and pushdown automata

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Using Pumping Lemma for CFLs, prove that $L = \{a^{n}b^{n}c^{n} \mid n \ge 0\}$ is not context-free.

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