Using Pumping Lemma for CFLs, prove that L = \{a^{n}b^{n}c^{n} \mid n — PYQDeck

PyQdeckBEU PYQ Archive Subjects

Back to the 2025 paper

Module 2: Context-free languages and pushdown automata

20257m

Using Pumping Lemma for CFLs, prove that $L = \{a^{n}b^{n}c^{n} \mid n \ge 0\}$ is not context-free.

Search Google Ask AI

Similar questions

FORMAL LANGUAGE & AUTOMATA THEORYWrite a short note on the Pumping Lemma for CFL.20213.5m Formal Language & Automata TheoryWrite a short note on: Pumping lemma for CFL20203.5m FORMAL LANGUAGE & AUTOMATA THEORYWrite short notes on: Pumping lemma for CFL.20237m Formal Language & Automata TheoryWrite short notes on: Pumping lemma for CFL20227m

PreviousExplain how ambiguity arises in the grammar E \rightarrow E + E \mid E \times E \mid id \mid (E). Remove the ambiguity by rewriting the grammar.NextExplain Linear Bounded Automata and its relationship with Context-Sensitive Languages.