Fundamentals of Engineering Drawing, Geometrical Constructions and Scales (6 hrs) · Engineering Graphics and Design

Engineering Scales - Scales on Drawings, Plain scale, Diagonal scale, Vernier scale

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Engineering Scales: Plain, Diagonal & Vernier Scales


1. Fundamental Principles of Engineering Scales

A scale is defined as the ratio of the linear dimension of an element of an object shown in the drawing to the real linear dimension of the same element of the object itself.

A. Representative Fraction (R.F.)

R.F.=Length of drawingActual length of object=Dimension on sheetActual dimension (in identical units)\text{R.F.} = \frac{\text{Length of drawing}}{\text{Actual length of object}} = \frac{\text{Dimension on sheet}}{\text{Actual dimension (in identical units)}}
  • Full Size Scale: R.F.=1:1\text{R.F.} = 1 : 1 (e.g., small machine components).
  • Reducing Scale: R.F.<1\text{R.F.} < 1 (e.g., 1:2,1:5,1:50,1:10001 : 2, 1 : 5, 1 : 50, 1 : 1000; used for buildings, large machines, geographical maps).
  • Enlarging Scale: R.F.>1\text{R.F.} > 1 (e.g., 2:1,5:1,10:12 : 1, 5 : 1, 10 : 1; used for microchips, watch mechanisms, precision instruments).

B. Unit Conversion Hierarchy

1 km=10 Hectometers (hm)=100 Decameters (dam)=1000 Meters (m)1 m=10 Decimeters (dm)=100 Centimeters (cm)=1000 Millimeters (mm)1 Mile=8 Furlongs=1760 Yards=5280 Feet1 Yard=3 Feet=36 Inches\begin{aligned} 1\text{ km} &= 10\text{ Hectometers (hm)} = 100\text{ Decameters (dam)} = 1000\text{ Meters (m)} \\ 1\text{ m} &= 10\text{ Decimeters (dm)} = 100\text{ Centimeters (cm)} = 1000\text{ Millimeters (mm)} \\ 1\text{ Mile} &= 8\text{ Furlongs} = 1760\text{ Yards} = 5280\text{ Feet} \\ 1\text{ Yard} &= 3\text{ Feet} = 36\text{ Inches} \end{aligned}

C. Length of Scale (L.O.S.)

L.O.S.=R.F.×Maximum length to be measured (M.L.)\text{L.O.S.} = \text{R.F.} \times \text{Maximum length to be measured ($M.L.$)}

(Standard practice: L.O.S. should always be converted to centimeters and usually lies between 15 cm15\text{ cm} and 20 cm20\text{ cm} for convenient sheet layout).


2. Plain Scale

A plain scale is a flat line graduated to measure two units (a main unit and its immediate subdivision, e.g., meters and decimeters, or kilometers and hectometers) or one unit with a single decimal place.

Subdivisions (dm)               Main Divisions (meters)
10 8 6 4 2 0         1              2              3              4
 | | | | | |---------|--------------|--------------|--------------|
[ ] [ ] [ ][         ][             ][             ][             ]

Standard Construction Rules:

  1. Calculate R.F.\text{R.F.} and L.O.S.\text{L.O.S.}.
  2. Draw a rectangle of length equal to L.O.S.\text{L.O.S.} and width between 5 mm5\text{ mm} and 10 mm10\text{ mm}.
  3. Divide the total length into NN equal parts corresponding to the maximum measurement capacity (M.L.M.L.).
  4. Zero Placement: Number the first dividing line as 00. Divisions to the right of 00 represent main units (1,2,3,…1, 2, 3, \dots).
  5. Divide the first division (to the left of 00) into smaller sub-units (1010 parts for metric units) and number it from right to left (0,1,2,…,100, 1, 2, \dots, 10).
  6. Write the R.F. clearly below or above the scale.

3. Diagonal Scale

A diagonal scale is used to measure three successive units (e.g., meters, decimeters, and centimeters) or a dimension up to two decimal places (e.g., 4.76 m4.76\text{ m}).

Principle of Diagonal Division:

The construction relies on the geometric property of similar right triangles:

  • In right triangle ABCABC, let base BC=1 unitBC = 1\text{ unit}.
  • Divide height ABAB into n=10n = 10 equal parts.
  • Horizontal lines drawn through points 1,2,…,91, 2, \dots, 9 have lengths proportional to their height:
Width at kth division=k10×BC=0.1k\text{Width at } k^{\text{th}}\text{ division} = \frac{k}{10} \times BC = 0.1k
   C
   |\
 9 |-|- 0.9
 8 |-|- 0.8
   | |
 2 |-|- 0.2
 1 |-|- 0.1
   +---+
   A   B

Step-by-Step Construction Procedure:

  1. Draw length of scale L.O.S.\text{L.O.S.}, with height H≈40–50 mmH \approx 40\text{–}50\text{ mm}.
  2. Divide length into main units. Place 00 at the first main mark.
  3. Subdivide the leftmost block horizontally into 1010 intermediate units (e.g., decimeters).
  4. Subdivide the vertical edge into 1010 smallest units (e.g., centimeters).
  5. Draw Diagonals: Join point 00 on the bottom line to point 11 on the top line; point 11 bottom to point 22 top, and so on.
  6. Reading a Dimension (e.g., 4.67 m4.67\text{ m}):
    • Move from 00 rightward to 4 m4\text{ m}.
    • Move from 00 leftward along the baseline to 6 dm6\text{ dm}.
    • Trace up the diagonal line of 6 dm6\text{ dm} to the 7th7^{\text{th}} horizontal centimeter line.

4. Vernier Scale

A Vernier scale consists of two parts: a Main Scale (MS) and a sliding auxiliary Vernier Scale (VS), enabling readings finer than the smallest main-scale division.

A. Direct (Forward) Vernier:

  • nn Vernier divisions equal (n−1)(n - 1) Main Scale divisions:
n⋅V=(n−1)⋅S  ⟹  V=n−1nSn \cdot V = (n - 1) \cdot S \implies V = \frac{n - 1}{n} S
  • Least Count (L.C.):
L.C.=S−V=S−(n−1n)S=Sn\text{L.C.} = S - V = S - \left(\frac{n - 1}{n}\right)S = \frac{S}{n}
  • The Vernier graduations read in the same direction as the main scale.

B. Retrograde (Backward) Vernier:

  • nn Vernier divisions equal (n+1)(n + 1) Main Scale divisions:
n⋅V=(n+1)⋅S  ⟹  V=n+1nSn \cdot V = (n + 1) \cdot S \implies V = \frac{n + 1}{n} S
  • Least Count (L.C.):
L.C.=V−S=(n+1n)S−S=Sn\text{L.C.} = V - S = \left(\frac{n + 1}{n}\right)S - S = \frac{S}{n}
  • The Vernier graduations read in the opposite direction to the main scale.

5. Solved Standard Exam Problem

Problem: On a map, an area of 144 cm2144\text{ cm}^2 represents an actual area of 36 km236\text{ km}^2. Construct a diagonal scale to measure up to 10 km10\text{ km}, showing kilometers, hectometers, and decameters. Show a distance of 7.46 km7.46\text{ km} on the scale.

Solution:

  1. Find R.F.:
Area Scale=144 cm236 km2=144 cm236×(105 cm)2=41010\text{Area Scale} = \frac{144\text{ cm}^2}{36\text{ km}^2} = \frac{144\text{ cm}^2}{36 \times (10^5\text{ cm})^2} = \frac{4}{10^{10}}
Linear R.F.=144 cm236 km2=12 cm6 km=12 cm6×105 cm=150,000\text{Linear R.F.} = \sqrt{\frac{144\text{ cm}^2}{36\text{ km}^2}} = \frac{12\text{ cm}}{6\text{ km}} = \frac{12\text{ cm}}{6 \times 10^5\text{ cm}} = \frac{1}{50,000}
  1. Calculate Length of Scale (L.O.S.):
L.O.S.=R.F.×Max Length=150,000×(10 km×100,000 cm/km)=1,000,00050,000=20 cm\text{L.O.S.} = \text{R.F.} \times \text{Max Length} = \frac{1}{50,000} \times (10\text{ km} \times 100,000\text{ cm/km}) = \frac{1,000,000}{50,000} = 20\text{ cm}
  1. Construction:
    • Draw a line of 20 cm20\text{ cm} and divide it into 1010 equal parts (each =1 km= 1\text{ km}).
    • Subdivide first 1 km1\text{ km} block horizontally into 1010 parts (each =1 hm=100 m= 1\text{ hm} = 100\text{ m}).
    • Divide vertical height (50 mm50\text{ mm}) into 1010 parts (each =1 dam=10 m= 1\text{ dam} = 10\text{ m}).
    • Draw diagonals across the first block.
    • Mark 7.46 km7.46\text{ km}: 7 km7\text{ km} to the right of 00 + 4 hm4\text{ hm} to the left of 00 + trace up diagonal to 6th6^{\text{th}} vertical line (6 dam6\text{ dam}).

6. Summary of Key Exam Points

  1. R.F. Calculation: Must always be reduced to identical units in numerator and denominator (R.F.\text{R.F.} is dimensionless).
  2. Area & Volume R.F.:
    • R.F.=Area on map/Actual area\text{R.F.} = \sqrt{\text{Area on map} / \text{Actual area}}
    • R.F.=Volume on drawing/Actual volume3\text{R.F.} = \sqrt[3]{\text{Volume on drawing} / \text{Actual volume}}
  3. Number of Units:
    • Plain scale = 22 units.
    • Diagonal scale = 33 units (or 22 decimals).
    • Vernier scale = 33 units (or precision fraction of smallest division).
  4. Zero Position: Zero is strictly placed at the boundary between the first subdivision block and the main scale divisions.
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