Electrochemistry, Corrosion & Colloidal (9 hrs) · Engineering Chemistry

Next-Gen Energy: H2-O2 and methanol (fuel cells, solar cells), Lubricants (Flash point, Fire point, acid value)

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Fuel Cells, Solar Cells & Lubricants

1. Fuel cells (continuous galvanic cells)

Fuel + oxidant fed continuously; no recharging needed, only fuel supply. General anode reaction: fuel oxidized releasing electrons; cathode: O2+4H++4e−→2H2OO_2 + 4H^+ + 4e^- \to 2H_2O.

(a) H₂–O₂ fuel cell (alkaline, ~1.23 V theoretical):

  • Anode: 2H2+4OH−→4H2O+4e−2H_2 + 4OH^- \to 4H_2O + 4e^-; cathode: O2+2H2O+4e−→4OH−O_2 + 2H_2O + 4e^- \to 4OH^-.
  • Overall: 2H2+O2→2H2O2H_2 + O_2 \to 2H_2O — only water as by-product. Used in Apollo spacecraft; needs pure H₂ storage.
    (b) Methanol fuel cell (DMFC):
  • Anode: CH3OH+H2O→CO2+6H++6e−CH_3OH + H_2O \to CO_2 + 6H^+ + 6e^-; cathode: 32O2+6H++6e−→3H2O\frac{3}{2}O_2 + 6H^+ + 6e^- \to 3H_2O.
  • Liquid fuel = easy storage for portable/laptop power; lower efficiency (methanol crossover, CO poisoning of Pt catalyst).

Fuel-cell advantages: 60–70% efficiency (vs ~35% thermal), silent, modular, clean. Limits: H₂ storage, catalyst cost (Pt), infrastructure.

2. Solar cells (photovoltaic)

p–n junction silicon: photons with E≥E \ge band gap (1.1 eV for Si) create electron–hole pairs; built-in junction field sweeps them apart → DC current.

I=IL−I0(eqV/kT−1)I = I_L - I_0\left(e^{qV/kT} - 1\right)
  • Single cell ~0.5–0.6 V; modules string cells to 12/24 V. Efficiency: mono-Si ~20–24%, poly ~16–18%.
  • Advantages: no fuel, no pollution, low maintenance. Limits: intermittent, area-hungry, storage needed, manufacturing energy cost.

3. Lubricants — why needed

Reduce friction, wear, heat; seal, protect from corrosion, carry away debris. Good lubricant: right viscosity, stable at working T, non-corrosive.

4. Flash point, fire point, acid value

  • Flash point: lowest T at which oil vapours momentarily flash (catch fire briefly) with a test flame. Abel/Pensky–Martens closed-cup apparatus.
  • Fire point: lowest T at which vapours burn continuously ≥ 5 s. Fire point ≈ flash point + 5–10 °C.
  • Low flash/fire point → fire hazard, volatile loss — lubricating oils need HIGH values (transformer oil > 140 °C).
  • Acid value: mg of KOH to neutralize free fatty acids in 1 g of oil:
Acid value=56.1×V×NW\text{Acid value} = \frac{56.1 \times V \times N}{W}

(VV = KOH volume mL, NN = normality, WW = oil weight g). High acid value = rancid/degraded oil, corrodes machinery — fresh edible/transformer oils need LOW values.

Numerical: 5 g oil needs 2 mL of 0.1 N KOH → acid value =56.1×2×0.1/5=2.24= 56.1 \times 2 \times 0.1/5 = 2.24 mg KOH/g.

Exam Points

  • H₂–O₂ and methanol cell reactions + 2 advantages (5 marks favourite).
  • Solar-cell working principle + band-gap idea (3 marks).
  • Flash vs fire point definitions + apparatus; acid-value formula + one numerical (3–5 marks).
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