Lasers and Optical Fiber (8hrs) · Engineering Physics

Basic principles (TIR, Acceptance angle and Numerical Aperture)

Watch lectures

Basic principles (TIR, Acceptance angle and Numerical Aperture)

1. Total Internal Reflection (TIR) — Guiding Principle

If light travels from denser (n1n_1) to rarer (n2<n1n_2<n_1), Snell's n1sinθ1=n2sinθ2n_1 sinθ_1 = n_2 sinθ_2. For θ1>θc=sin−1(n2/n1)θ_1 > θ_c = sin^{-1}(n_2/n_1), sinθ2>1sinθ_2>1 impossible ⇒ no refraction, 100% reflection inside denser medium — TIR. Fibre guides by TIR at core-cladding.

2. Acceptance Angle (θaθ_a) and Cone

Light entering fibre from air (n0≈1n_0≈1) at angle θ0θ_0 to axis refracts into core at θrθ_r, then hits core-cladding at φ=90°−θrφ =90°-θ_r. For TIR need φ≥θcφ ≥ θ_c ⇒

sinθa=√[n12−n22]/n0sinθ_a = √[n_1² - n_2²]/n_0

Derivation: n0sinθa=n1sinθrn_0 sinθ_a = n_1 sinθ_r, and sinθr=cosφ≤cosθc=√[1−(n2/n1)2]sinθ_r = cosφ ≤ cosθ_c = √[1-(n_2/n_1)²] ⇒ above.

θa=sin−1(√[n12−n22]/n0)θ_a = sin^{-1}( √[n_1² - n_2²]/n_0)

Rays within acceptance cone half-angle θaθ_a are guided; outside leak as refracted.

For fibre in air n0=1n_0=1:

sinθa=√[n12−n22]sinθ_a = √[n_1² - n_2²]

3. Numerical Aperture (NA)

NA = measure of light-gathering ability:

NA=n0sinθa=√[n12−n22]NA = n_0 sinθ_a = √[n_1² - n_2²]

(For air, NA=√[n12−n22]NA =√[n_1²-n_2²]). Also

NA≈n1√[2Δ]NA ≈ n_1√[2Δ]

where Δ=(n1−n2)/n1Δ=(n_1-n_2)/n_1.

  • Large ΔΔ (large index step) ⇒ large NANA ⇒ larger acceptance cone and more modes, but more modal dispersion.

Typical: single-mode NA≈0.12NA≈0.12 (θa≈7°θ_a≈7°), multimode NA≈0.22NA≈0.22 (≈12°≈12°).

4. Inter-relation

NANA determines number of modes:

V−number=(2πa/λ)NAV-number = (2π a/λ) NA

where aa = core radius. Single-mode when V<2.405V<2.405 (cutoff of first higher mode).

5. Worked Examples

(a) n1=1.48, n2=1.46, air: NA=√(1.48²-1.46²)=√(0.0588)≈0.242, θ_a≈14° ✓
(b) Want to increase NA? Raise Δ by Ge-doping core.
(c) Fibre in water n0=1.33: effective NA reduces? Actually NA= n0 sinθ_a still √[n1²-n2²] independent of n0? Wait formula NA=n0 sinθ_a =√[n1²-n2²] so θ_a = sin^{-1}(NA/n0) ⇒ smaller θ in water.
(d) V-number for a=25 µm (core 50 µm), λ=1300 nm, NA=0.22 ⇒ V=2π·25e-6·0.22/1.3e-6≈26.6 ⇒ multimode.

6. Exam Points

  • State TIR condition θ1>θcθ_1>θ_c — 3 marks, frequent.
  • Derive NA=√[n12−n22]NA=√[n_1²-n_2²] and θa=sin−1(NA/n0)θ_a =sin^{-1}(NA/n_0) — 5-7 marks, very frequent (almost certain).
  • Compute θa,NAθ_a, NA for given n1,n2n_1,n_2 — 5 marks, very frequent.
  • Mention acceptance cone diagram — 5 marks, frequent.
Official AppAndroid App

PYQDeck for Android

Solve BEU previous-year exam papers anywhere, anytime. Fast search, offline paper viewing, and step-by-step solutions designed specifically for your phone.

← All Engineering Physics modules