Basic Electrical Circuits (8hrs) · Basics of Electrical & Electronics Engineering

voltage divider rule

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voltage divider rule

1. What Voltage Divider Is

Voltage divider = series circuit rule to find how voltage splits across series resistors from total voltage, without solving whole circuit.

For two resistors R1,R2R_1,R_2 in series, total voltage VtotalV_{total} across them splits as:

V1=Vtotal⋅R1/(R1+R2),V2=Vtotal⋅R2/(R1+R2)V_1 = V_{total}· R_1/(R_1+R_2) , V_2 = V_{total}· R_2/(R_1+R_2)

i.e., voltage across a resistor = total × its resistance / sum. Larger RR gets larger share (proportional to RR).

Derivation: same current

I=Vtotal/(R1+R2)I = V_{total}/(R_1+R_2)

, then

V1=I⋅R1=Vtotal⋅R1/(R1+R2)V_1 = I·R_1 = V_{total}·R_1/(R_1+R_2)

2. For More Than Two Resistors

For nn series RiR_i, voltage across RkR_k:

Vk=Vtotal⋅Rk/ΣRiV_k = V_{total}· R_k / Σ R_i

3. Generalization to AC Impedance

For series impedances ZiZ_i,

Vk=Vtotal⋅Zk/ΣZiV_k = V_{total}· Z_k / Σ Z_i

(phase matters).

4. Worked Examples

(a) 10V across series 2Ω+3Ω: V2Ω=10·2/5=4V, V3Ω=6V ✓ Check: 4+6=10, current 2A.

(b) Need to create 6V from 12V source with equal resistors: R1=R2 ⇒ V=6V each ✓

(c) Series 2Ω,3Ω,6Ω total 11Ω at 22V: V2=4V, V3≈6V, V6=12V ✓

(d) Loaded divider: divider R1,R2 with load RL across R2: R_eq2 = R2||RL, then V2 = Vtotal·R_eq2/(R1+R_eq2) < unloaded.

(e) Potentiometer is variable voltage divider.

(f) Why not for parallel? Parallel uses current divider.

5. Exam Points

  • State V1=V⋅R1/(R1+R2)V_1=V·R_1/(R_1+R_2) for two series — 5 marks, very frequent (almost certain).
  • Derive via I=V/(R1+R2)I=V/(R_1+R_2) — 3-5 marks, frequent.
  • Solve numerical with 2 or 3 series, and loaded divider — 5-7 marks, very frequent.
  • Distinguish from current divider (parallel) — 3 marks.
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