BJT Applications: CE configuration as amplifier
1. What CE Configuration Is
CE (Common-Emitter) = emitter common to input and output: input at base-emitter, output at collector-emitter (emitter grounded for AC via capacitor). It is the most used BJT amplifier configuration because it gives high voltage, current, and power gain, and phase inversion ().
Alternatives: CB (common-base, voltage gain but , low input , high output) and CC (emitter follower, current gain, voltage gain ≈1, buffer) — but CE is standard.
2. Circuit (bias + AC)
Vcc (12V) → Rc (collector resistor, e.g., 2kΩ) → Collector → Emitter → Re (emitter resistor with bypass Ce) → Ground
Base → voltage divider R1,R2 (e.g., 40k/10k) setting Vb≈2V ⇒ Ve=1.3V ⇒ Ie≈1.3mA, Q-point → coupling capacitors Cin, Cout block DC, pass AC.
Bias (Q-point): sets and in active region (e.g., ) so signal swing not clipped.
3. Working as Amplifier
- Small AC input (e.g., 10mV) modulates :
where
(e.g., 1mA ⇒ 25Ω? Actually , ).
- Collector current
with transconductance
mS (e.g., 1mA ⇒40mS).
- Voltage gain:
where
, negative sign = 180° phase inversion (when base goes up, collector goes down due to drop).
- For , ⇒ (40mS·2k).
4. Characteristics
| Feature | CE Amplifier |
|---|---|
| Voltage gain | High (-50 to -500) |
| Current gain | High |
| Power gain | High |
| Input | Moderate (~kΩ) |
| Output | Moderate-high |
| Phase | 180° inverted (input up ⇒ output down) |
5. Worked Design
Need Av=-100 with Ic=2mA: gm=80mS ⇒ Rc=Av/gm=1.25kΩ ⇒ choose 1.2kΩ.
Input rπ=β/gm≈100/80mS=1.25kΩ, with bias divider 10k ⇒ Zin≈1.1kΩ.
6. Exam Points
- Draw CE amplifier with voltage divider bias, , , — 7 marks, very frequent (almost certain to ask CE circuit).
- Explain , bias, and with 180° — 7-10 marks, very frequent (the most common amplifier question).
- Mention high voltage/current/power gain — 3-5 marks, frequent.
- Distinguish CE vs CC vs CB (gain, ) — 5 marks, frequent.