Linear dependence
1. Linear Combination
A vector v is a linear combination of the vectors v₁, v₂, …, vₙ if scalars c₁, c₂, …, cₙ exist such that
The set of all such combinations is the span of {v₁, …, vₙ}.
2. Definition of Dependence and Independence
The vectors v₁, v₂, …, vₙ are linearly dependent if there exist scalars c₁, …, cₙ, not all zero, such that
They are linearly independent if this equation has only the trivial solution c₁ = c₂ = … = cₙ = 0.
In words: a dependent set contains redundant vectors — at least one of them can be written as a combination of the others. An independent set contains no redundancy; every vector adds a new direction.
3. Geometric Meaning
| Number of vectors | In R² | In R³ |
|---|---|---|
| 2 dependent | both on the same line (parallel) | same line |
| 2 independent | different directions | different directions |
| 3 dependent | — | all lie in one plane through the origin (coplanar) |
| 3 independent | — | span the whole space R³ |
Also geometrically obvious: a set containing the zero vector is always dependent (take its coefficient as 1 and the rest 0).
4. Three Tests to Decide Dependence
| Test | Rule |
|---|---|
| 1. Equation test (definition) | Solve c₁v₁ + … + cₙvₙ = 0. Non-trivial solution ⇒ dependent; only the trivial solution ⇒ independent. |
| 2. Rank test | Arrange the vectors as the rows of a matrix A. Then ρ(A) = n ⇒ independent, ρ(A) < n ⇒ dependent, where n = number of vectors. |
| 3. Determinant test | If there are exactly n vectors in Rⁿ, form the n × n matrix. det ≠ 0 ⇒ independent; det = 0 ⇒ dependent. |
5. Standard Theorems
- Any set containing the zero vector is linearly dependent.
- Any set of more than n vectors in Rⁿ is necessarily dependent.
- A subset of a linearly independent set is linearly independent; a superset of a dependent set is dependent.
- If a set is dependent, then at least one vector is a linear combination of the others (but not necessarily every one).
- n linearly independent vectors in Rⁿ form a basis of Rⁿ (see the next topic).
- If {v₁, …, vₙ} is independent and w is not in its span, then {v₁, …, vₙ, w} is also independent.
Check : v1 = (1, 2, 3) , v2 = (3, -2, 1) , v3 = (1, -6, -5)
Determinant test (3 vectors in R^3):
| 1 2 3 |
det | 3 -2 1 | = 1[(-2)(-5) - (1)(-6)] - 2[(3)(-5) - (1)(1)] + 3[(3)(-6) - (-2)(1)]
| 1 -6 -5 |
= 1(10 + 6) - 2(-15 - 1) + 3(-18 + 2)
= 16 + 32 - 48 = 0 ⇒ D E P E N D E N T
The actual relation (find it by solving the homogeneous system):
2 v1 - v2 + v3 = (2 - 3 + 1, 4 + 2 - 6, 6 - 1 - 5) = (0, 0, 0) ✓
so c1 = 2 , c2 = -1 , c3 = 1 is a non-trivial solution, confirming dependence.
9. Dependence and Rank — the Connection to Remember
For n vectors in Rᵐ, dependence is exactly a rank deficiency: if the vectors are written as rows of A, then
The number of independent vectors in the set equals the rank, and the remaining (n − ρ) vectors are redundant combinations of them. This single idea covers the equation test, the determinant test (for square matrices det = 0 means rank < n) and the "more than n vectors in Rⁿ" rule.
10. Exam Points
- Define linear dependence and independence of vectors, with the equation c₁v₁ + … + cₙvₙ = 0 — 5 marks, almost certain.
- Test whether a given set of vectors in R³ is dependent (determinant or rank method) — 5-7 marks, very frequent.
- Find the value(s) of k for which a given set of vectors is linearly dependent — 5-7 marks, very frequent.
- Show that any set containing the zero vector is dependent — 3 marks.
- Show that more than n vectors in Rⁿ are always dependent — 3-5 marks.
- Express one of three dependent vectors as a linear combination of the other two — 5 marks.
- State the geometric meaning of dependence for 2 and 3 vectors — 3 marks.