Maclaurin's theorem and related problems
1. Maclaurin as Taylor at
Set in Taylor:
is Maclaurin's theorem for . Remainder (Lagrange) with .
This is the workhorse for small expansions about the origin — most exam expansions are Maclaurin, not general Taylor.
2. When to Use Maclaurin Directly vs Product of Single-Variable Series
Both work; pick faster:
- If or , expand singly and multiply — e.g., .
- If mixes inseparably (), use formula or substitute .
3. Worked Examples — Standard Maclaurin Problems
(a) f(x,y)= e^{x} sin y to third order about (0,0):
e^x =1+x+x²/2+x³/6 ; sin y = y - y³/6 ; product keep total degree ≤3:
f ≈ (1+x+x²/2)(y - y³/6) ≈ y + x y + x² y/2 - y³/6 - x y³/6 (last term degree 4? Actually x y³ degree 4 → drop for order 3) ⇒ y + x y + (x² y)/2 - y³/6 ✓
Check via formula: f(0,0)=0, f_x= e^x sin y→0, f_y= e^x cos y→1, etc. matches.
(b) f(x,y)= log(1+ x + y) to second order:
t=x+y small: log(1+t)= t - t²/2 + t³/3 ; ⇒ f≈ (x+y) - (x²+2xy+y²)/2 ✓
Remainder O((x+y)³).
(c) f(x,y)= sin(x+y) + cos(x+y) mixture? Expand sin→(x+y)-(x+y)³/6, cos→1-(x+y)²/2 ⇒ sum ✓
(d) f(x,y)= (1+x+y)^{1/2} to second order: use binomial (1+t)^{1/2}=1+t/2 -t²/8 ; t=x+y ⇒ 1+(x+y)/2 -(x+y)²/8 ✓
(e) f(x,y)= e^{x y} to second order: t= x y ⇒ e^t=1+t +t²/2 ⇒ 1+ x y + x² y²/2 (≈1+xy for order 2) ✓
(f) Approximate value: f(0.1,0.05)= e^{0.1} cos 0.05 using Maclaurin second order from Taylor topic:
≈1+0.1+(0.01-0.0025)/2=1.10375 vs actual 1.10396 error 0.00021 (<R3 bound) ✓
4. Remainder Estimate for Maclaurin
Lagrange . Bound by max third derivative in disc . For , .
5. Convergence Domain
- : all .
- : .
- : .
Mention if question asks for region of validity.
6. Exam Points
- State Maclaurin's theorem for with remainder — 3-5 marks, frequent.
- Expand to second/third order — 7 marks, very frequent.
- Use expansion to approximate and bound error — 5 marks, frequent.
- Show product method matches formula — 5 marks.