Minima for functions of several variables
1. Minima — Same Test as Maxima, Opposite Sign
A local minimum at means near . Interior minima need same necessary condition:
and same discriminant:
| Local minimum (bowl up) | |
|---|---|
| Local maximum | |
| Saddle (neither) | |
| Inconclusive |
Only the sign of flips between maxima/minima — all else identical to previous topic. Many examiners merge maxima+minima into one question; this split reflects syllabus wording.
2. Global vs Local
Local minima may not be least overall. On a closed bounded domain, global minimum is least among: interior stationary points classified as minima and boundary points (where may still be extremal). Without boundary, may have no global extremum.
3. Worked Examples Focused on Minima
(a) f(x,y)= x^2 + y^2 + x^2 y +4 (simple bowl):
f_x=2x+2x y=2x(1+y)=0 ⇒ x=0 or y=-1 ; f_y=2y+x^2=0
Case x=0 ⇒ y=0 ⇒ (0,0): A=2, B=0, C=2 ⇒ D=4>0, A>0 ⇒ MINIMUM value 4 ✓
Case y=-1 ⇒ x^2=2 ⇒ (±√2,-1): A=0, B=2√2, C=2 ⇒ D= -8 <0 ⇒ saddles ✓
So only (0,0) is minimum.
(b) f(x,y)= x^4 + y^4 -2(x-y)^2 ? Check: f_x=4x^3-4(x-y), f_y=4y^3+4(x-y)
Stationary at (0,0) and (±...); classify ⇒ minima at non-zero, saddle at origin ✓
(c) f(x,y)= (x^2+y^2) e^{-(x^2+y^2)}? Actually has maximum at r=1? But minima at (0,0) and at ∞?
Need check: radial r^2 e^{-r^2} → max at r=1, min at 0 (0) and →0 at ∞ (not interior) ✓
(d) Cost-type: Production cost C(x,y)=2x^2+3y^2-2x y -3x -4y +5 : f_x=4x-2y-3=0, f_y=6y-2x-4=0 ⇒ solve x=1, y=1 ⇒ A=4, C=6, B=-2 ⇒ D=24-4=20>0, A>0 ⇒ MINIMUM cost 0? Actually C(1,1)=0 ⇒ minimum ✓
4. Using Completion of Squares for Simple Quadratics
If , the stationary point solves linear ; decides type. This matches the quadratic-form theory from Module 1.
5. Exam Points
- Find stationary points and show one is minimum — 5-7 marks, very frequent.
- Distinguish minima from maxima via vs — 3 marks.
- Second-derivative test same for maxima/minima — state once, apply twice — 7 marks, almost certain (often combined question: "find maxima and minima").
- Global minima on closed domain — include boundary via Lagrange (next topic) — 7 marks.