Integral Calculus (9hrs) · Engineering Mathematics - I

Change the order of integration

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Change the order of integration

1. Why Change Order

Some iterated integrals cannot be done in given order (inner integral non-elementary, e.g. ∫ey2dy∫ e^{y²} dy) or region description is messy. Changing order (dy dx↔dx dydy\,dx ↔ dx\,dy) often makes it elementary or simpler. Fubini guarantees equality when ff continuous (absolute integrability).

2. Method — Sketch and Re-describe DD

Given I=∫x=ab∫y=g1(x)g2(x)f(x,y)dydxI = ∫_{x=a}^{b} ∫_{y=g_1(x)}^{g_2(x)} f(x,y) dy dx:

  1. Sketch DD bounded by y=g1(x),y=g2(x),x=a,x=by=g_1(x), y=g_2(x), x=a, x=b.
  2. Describe DD the other way: x=h1(y)toh2(y)x = h_1(y) to h_2(y), y∈[c,d]y∈[c,d].
  3. Write I=∫y=cd∫x=h1(y)h2(y)f(x,y)dxdyI = ∫_{y=c}^{d} ∫_{x=h_1(y)}^{h_2(y)} f(x,y) dx dy.

For DD that is not both x- and y-simple, split into pieces in new order.

3. Worked Examples

(a) I = ∫_{0}^{1}∫_{y}^{1} e^{y²}?? Actually classic: ∫_{0}^{1}∫_{x}^{1} e^{y²} dy dx cannot do inner e^{y²}?
    Reverse: D: x 0→1, y x→1 is triangle y≥x. Other way: y 0→1, x 0→y:
    I = ∫_{0}^{1}∫_{0}^{y} e^{y²} dx dy = ∫_{0}^{1} y e^{y²} dy = (e-1)/2 ✓

(b) I = ∫_{0}^{a}∫_{y}^{a} x²/√(x²+y²) ?? Often polar needed but order change may help.

(c) I = ∫_{0}^{1}∫_{y}^{1} sin(y²) dy dx? No sin? Actually ∫_{0}^{1}∫_{x}^{1} sin(y²) dy dx = ?
    D as above: = ∫_{0}^{1}∫_{0}^{y} sin(y²) dx dy = ∫_{0}^{1} y sin(y²) dy = (1-cos1)/2 ✓

(d) I = ∫_{0}^{2}∫_{y/2}^{1} e^{x²} dx dy? Provided? Another: ∫_{0}^{1}∫_{0}^{√(1-x²)} f? Change.

(e) D bounded by y= x² and y= x: ∫_{0}^{1}∫_{x²}^{x} f dy dx ; other order: y 0→1, x y→√y
    ⇒ ∫_{0}^{1}∫_{y}^{√y} f dx dy ✓

(f) I = ∫_{0}^{4}∫_{y/2}^{2} e^{x²} ?? D: y=0→4, x= y/2 →2 is same as x 0→2, y 0→2x
    So I = ∫_{0}^{2}∫_{0}^{2x} e^{x²}? Wait integrand? Example shows region re-description.

(g) Sometimes need two pieces: D = 0≤x≤1, 0≤y≤x plus 1≤x≤2, 0≤y≤2-x? Combined gives triangle with apex.

4. Dirichlet and Other Tricks

If integrand separates as f(x)g(y)f(x)g(y) over rectangle, ∬=(∫f)(∫g)∬ = (∫f)(∫g) — no order needed. But change is essential when inner antiderivative is not elementary.

5. Exam Points

  • Given ∫ab∫g1(x)g2(x)fdydx∫_{a}^{b}∫_{g_1(x)}^{g_2(x)} f dy dx, change to dx dydx\,dy with new limits — 5-7 marks, very frequent.
  • Evaluate originally non-elementary ∫∫ey2∫∫ e^{y²} or siny2/ysin y² / y via change — 7 marks, very frequent.
  • Sketch region and split if needed — 5 marks, frequent.
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