Cylindrical polar co-ordinates
1. Why Cylindrical (vs Spherical)
For solids with circular symmetry about an axis (usually -axis) but not spherical — e.g., cylinder , cone , paraboloid — cylindrical is simpler than spherical or Cartesian. It is the 3D extension of polar in .
2. Transformation and Jacobian
with and volume element:
(Jacobian ). Do not confuse with spherical's — cylindrical keeps .
3. Limits
- Cylinder : .
- Cone , : for each , , .
- Paraboloid : or .
- Between cylinders .
4. Worked Examples
(a) Volume of cylinder radius a height h: V= ∫_{0}^{2π}∫_{0}^{a}∫_{0}^{h} r dz dr dθ = π a² h ✓
(b) ∭_{cylinder} (x²+y²) dV : = ∫_{0}^{2π}∫_{0}^{a}∫_{0}^{h} r²· r dz dr dθ =2π h·a⁴/4 = π a⁴ h/2 ✓
Without cylindrical, Cartesian limits messy.
(c) ∭_{paraboloid z = x²+y² below z=4} 1 dV (volume under paraboloid): D: r 0→2? Since z=r² → top z=4 ⇒ r=2
Using order r→z: V= ∫_{0}^{2π}∫_{0}^{2}∫_{r²}^{4} r dz dr dθ =2π·∫_{0}^{2}(4 -r²)r dr =8π ✓
Using order z→r: V= ∫_{0}^{4}∫_{0}^{√z} 2π r dr dz =π·∫_{0}^{4} z dz =8π same.
(d) Mass of cylinder with density ρ = k z: Mass= ∫_{0}^{2π}∫_{0}^{a}∫_{0}^{h} k z·r dz dr dθ = π a² k h²/2 ✓
(e) Moment of inertia of cylinder about z-axis: I_z = ∭ (x²+y²) dM ; with ρ constant ⇒ (1/2) M a² (standard).
(f) Cone volume? Cone r=z? Actually cone vertex at origin opening upward: V= ∫_{0}^{h} π r(z)² dz = π∫_{0}^{h} z² dz = π h³/3 ✓ matches cylindrical.
5. Choose Cylindrical vs Spherical vs Cartesian (exam tip)
- with free / linear in → cylindrical.
- or cone with apex at origin → spherical (sometimes also cylindrical for cone).
- Box or plane → Cartesian.
6. Exam Points
- Convert over cylinder/cone/paraboloid to — 7 marks, very frequent.
- Evaluate , over cylinder/cone — 7 marks, frequent.
- Volume via cylindrical — 5 marks, frequent.
- State vs — 3 marks.