Integral Calculus (9hrs) · Engineering Mathematics - I

Cylindrical polar co-ordinates

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Cylindrical polar co-ordinates

1. Why Cylindrical (vs Spherical)

For solids with circular symmetry about an axis (usually zz-axis) but not spherical — e.g., cylinder x2+y2≤a2x²+y² ≤ a², cone z=rz = r, paraboloid z=r2z = r² — cylindrical (r,θ,z)(r,θ,z) is simpler than spherical or Cartesian. It is the 3D extension of polar in xyxy.

2. Transformation and Jacobian

x=rcosθ,y=rsinθ,z=z,r≥0,θ∈[0,2π),zfreex = r cosθ , y = r sinθ , z = z , r≥0, θ∈[0,2π), z free

with x2+y2=r2x²+y² = r² and volume element:

dV=rdrdθdzdV = r dr dθ dz

(Jacobian =r= r). Do not confuse with spherical's r2sinφr² sinφ — cylindrical keeps zz.

3. Limits

  • Cylinder x2+y2≤a2,0≤z≤hx²+y² ≤ a², 0≤z≤h: r0→a,θ0→2π,z0→hr 0→a, θ 0→2π, z 0→h.
  • Cone z=√(x2+y2)=rz = √(x²+y²) = r, 0≤z≤h0≤z≤h: for each zz, r0→zr 0→z, θ0→2πθ 0→2π.
  • Paraboloid z=r2,0≤z≤hz = r², 0≤z≤h: r0→√zr 0→√z or zr2→hz r²→h.
  • Between cylinders a≤r≤ba≤r≤b.

4. Worked Examples

(a) Volume of cylinder radius a height h: V= ∫_{0}^{2π}∫_{0}^{a}∫_{0}^{h} r dz dr dθ = π a² h ✓

(b) ∭_{cylinder} (x²+y²) dV : = ∫_{0}^{2π}∫_{0}^{a}∫_{0}^{h} r²· r dz dr dθ =2π h·a⁴/4 = π a⁴ h/2 ✓
    Without cylindrical, Cartesian limits messy.

(c) ∭_{paraboloid z = x²+y² below z=4} 1 dV (volume under paraboloid): D: r 0→2? Since z=r² → top z=4 ⇒ r=2
    Using order r→z: V= ∫_{0}^{2π}∫_{0}^{2}∫_{r²}^{4} r dz dr dθ =2π·∫_{0}^{2}(4 -r²)r dr =8π ✓
    Using order z→r: V= ∫_{0}^{4}∫_{0}^{√z} 2π r dr dz =π·∫_{0}^{4} z dz =8π same.

(d) Mass of cylinder with density ρ = k z: Mass= ∫_{0}^{2π}∫_{0}^{a}∫_{0}^{h} k z·r dz dr dθ = π a² k h²/2 ✓

(e) Moment of inertia of cylinder about z-axis: I_z = ∭ (x²+y²) dM ; with ρ constant ⇒ (1/2) M a² (standard).

(f) Cone volume? Cone r=z? Actually cone vertex at origin opening upward: V= ∫_{0}^{h} π r(z)² dz = π∫_{0}^{h} z² dz = π h³/3 ✓ matches cylindrical.

5. Choose Cylindrical vs Spherical vs Cartesian (exam tip)

  • x2+y2≤a2x²+y² ≤ a² with zz free / linear in zz → cylindrical.
  • x2+y2+z2≤a2x²+y²+z² ≤ a² or cone with apex at origin → spherical (sometimes also cylindrical for cone).
  • Box or plane z=a−x−yz = a - x - y → Cartesian.

6. Exam Points

  • Convert ∭Vf(x,y,z)dV∭_{V} f(x,y,z) dV over cylinder/cone/paraboloid to ∭f(r,θ,z)rdrdθdz∭ f(r,θ,z) r dr dθ dz — 7 marks, very frequent.
  • Evaluate ∭(x2+y2)∭ (x²+y²), ∭z∭ z over cylinder/cone — 7 marks, frequent.
  • Volume via cylindrical — 5 marks, frequent.
  • State dV=rdrdθdzdV = r dr dθ dz vs r2sinφdrdφdθr² sinφ dr dφ dθ — 3 marks.
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