Statement of Green's
1. Statement — Green's Theorem in the Plane
Let be a positively oriented (counter-clockwise), piecewise smooth, simple closed curve in the -plane, and the region it encloses. If have continuous first partials on an open region containing , then:
The line integral is taken once around in the positive sense (region always to left as you walk). This converts a closed line integral (circulation) to a double integral of 's component ( ⇒ ).
2. Two Special Forms
- Tangential (circulation) form above.
- Normal (flux) form:
(with ) — the 2D divergence theorem (often called Green).
3. Why Useful
- Computes difficult closed line integrals by doing easier double integral (often is constant/simple).
- Proves path independence when on simply connected .
- Gives area formula: choose ⇒ ⇒
4. Worked Examples
(a) Evaluate ∮_{C} (-y dx + x dy) where C is circle x²+y²=a² counter-clockwise:
P=-y, Q=x ⇒ Q_x=1, P_y=-1 ⇒ Q_x-P_y=2 ⇒ ∮ =∬_{D}2 dA=2·πa²=2πa² ✓ matches earlier direct 2πa².
(b) ∮_{C} x² y dx + x y² dy over triangle? Compute Q_x = y², P_y = x² ⇒ integrand y² - x² double integral.
(c) Area of ellipse x²/a²+ y²/b²=1: param x=a cos t, y=b sin t, t 0→2π ⇒ 1/2∮ x dy - y dx =1/2∫_{0}^{2π}ab dt =πab ✓
(d) Need orientation: if C clockwise, ∮ = -∬ (sign flips).
(e) If P,Q have singularities inside D (e.g., F= -y/(x²+y²) i+ x/(x²+y²) j), Green fails unless punctured — ∮ may be 2π not zero, showing hole matters.
5. Conditions and Pitfalls
- must be closed, simple, positively oriented; must be on (no singularities inside).
- If multiply connected (hole), (subtract holes).
- Don't mix with forms.
6. Exam Points
- State Green's theorem — 3-5 marks, almost certain.
- Evaluate via for circle/rectangle/triangle — 7 marks, very frequent.
- Area via — 5 marks, frequent.
- Show failure when singularity inside — 5 marks, occasional.