Vector Calculus (8hrs) · Engineering Mathematics - I

Statement of Green's

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Statement of Green's

1. Statement — Green's Theorem in the Plane

Let CC be a positively oriented (counter-clockwise), piecewise smooth, simple closed curve in the xyxy-plane, and DD the region it encloses. If P(x,y),Q(x,y)P(x,y), Q(x,y) have continuous first partials on an open region containing DD, then:

∮CPdx+Qdy=∬D(∂Q/∂x−∂P/∂y)dA∮_{C} P dx + Q dy = ∬_{D} (∂Q/∂x - ∂P/∂y) dA

The line integral is taken once around CC in the positive sense (region always to left as you walk). This converts a closed line integral (circulation) to a double integral of curlFcurl F's kk component (F=Pi+QjF = P i+Q j ⇒ ∇×F=(Qx−Py)k∇×F = (Q_x -P_y)k).

2. Two Special Forms

  • Tangential (circulation) form above.
  • Normal (flux) form:
∮CPdy−Qdx=∬D(∂P/∂x+∂Q/∂y)dA=∬D∇⋅FdA∮_{C} P dy - Q dx = ∬_{D} (∂P/∂x+ ∂Q/∂y) dA =∬_{D} ∇·F dA

(with F=Pi+QjF=P i+Q j) — the 2D divergence theorem (often called Green).

3. Why Useful

  • Computes difficult closed line integrals by doing easier double integral (often Qx−PyQ_x-P_y is constant/simple).
  • Proves path independence when Qx−Py=0Q_x-P_y=0 on simply connected DD.
  • Gives area formula: choose P=−y/2,Q=x/2P=-y/2, Q=x/2 ⇒ Qx−Py=1Q_x-P_y=1 ⇒
Area(D)=1/2∮Cxdy−ydxArea(D)= 1/2 ∮_{C} x dy - y dx

4. Worked Examples

(a) Evaluate ∮_{C} (-y dx + x dy) where C is circle x²+y²=a² counter-clockwise:
    P=-y, Q=x ⇒ Q_x=1, P_y=-1 ⇒ Q_x-P_y=2 ⇒ ∮ =∬_{D}2 dA=2·πa²=2πa² ✓ matches earlier direct 2πa².

(b) ∮_{C} x² y dx + x y² dy over triangle? Compute Q_x = y², P_y = x² ⇒ integrand y² - x² double integral.

(c) Area of ellipse x²/a²+ y²/b²=1: param x=a cos t, y=b sin t, t 0→2π ⇒ 1/2∮ x dy - y dx =1/2∫_{0}^{2π}ab dt =πab ✓

(d) Need orientation: if C clockwise, ∮ = -∬ (sign flips).

(e) If P,Q have singularities inside D (e.g., F= -y/(x²+y²) i+ x/(x²+y²) j), Green fails unless punctured — ∮ may be 2π not zero, showing hole matters.

5. Conditions and Pitfalls

  • CC must be closed, simple, positively oriented; P,QP,Q must be C1C¹ on DD (no singularities inside).
  • If DD multiply connected (hole), ∮outer−∮inner=∬∮_{outer} -∮_{inner}=∬ (subtract holes).
  • Don't mix Pdx+QdyPdx+Qdy with Pdy−QdxPdy - Qdx forms.

6. Exam Points

  • State Green's theorem — 3-5 marks, almost certain.
  • Evaluate ∮CPdx+Qdy∮_{C} Pdx+Qdy via ∬D(Qx−Py)dA∬_{D}(Q_x-P_y)dA for circle/rectangle/triangle — 7 marks, very frequent.
  • Area via 1/2∮xdy−ydx1/2∮ x dy -y dx — 5 marks, frequent.
  • Show failure when singularity inside — 5 marks, occasional.
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