independence of vectors in R^n space
1. The Space Rⁿ
Rⁿ is the set of all ordered n-tuples of real numbers, written as row vectors (x₁, x₂, …, xₙ) or column vectors. With the usual addition and scalar multiplication it is a vector space, and its dimension is n.
The standard (canonical) basis of Rⁿ is the set of unit vectors
In R² this is i, j = (1,0), (0,1); in R³ it is i, j, k = (1,0,0), (0,1,0), (0,0,1). Every vector of Rⁿ is a unique combination of these: (a, b, c) = a i + b j + c k.
2. Four Definitions That Fit Together
| Term | Meaning |
|---|---|
| Span | The set of all linear combinations of the given vectors |
| Spanning set | A set whose span is the whole space (every vector can be built from them) |
| Linearly independent set | c₁v₁ + … + cₙvₙ = 0 only when all cᵢ = 0 — no vector is redundant |
| Basis | A set that is both linearly independent and spanning — the minimum number of vectors that reach every point of the space |
| Dimension | The number of vectors in any basis of the space (well-defined: all bases of a space have the same size) |
Mnemonics: independent = no redundancy, spanning = no gaps, basis = neither redundancy nor gaps.
3. The Independence Theorems for Rⁿ
- Maximum size. In Rⁿ, at most n vectors can be linearly independent. Any set of n + 1 or more vectors in Rⁿ is dependent.
- Minimum size for spanning. Fewer than n vectors can never span Rⁿ (they span at most a subspace of smaller dimension).
- Exactly n is the sweet spot. Any set of exactly n linearly independent vectors in Rⁿ is automatically a basis of Rⁿ (it necessarily spans). Equivalently, n vectors in Rⁿ span Rⁿ ⇔ they are independent ⇔ the n × n matrix of the vectors is non-singular (det ≠ 0).
- Dimension of a subspace. If W is a subspace of Rⁿ then 0 ≤ dim W ≤ n; dim W = n only when W = Rⁿ.
- Rank link. For vectors written as rows of A: the number of independent vectors = ρ(A); the row space of A has dimension ρ(A), and so does the column space — this is the meaning of "row rank = column rank".
Given m vectors in R^n:
┌── m > n ──────────────────────────► DEPENDENT (by theorem 1, no work needed)
└── m ≤ n
└── arrange them as rows of A (m × n)
└── reduce to echelon form
├── number of non-zero rows = m ──► INDEPENDENT
└── number of non-zero rows < m ──► DEPENDENT
Special case m = n : write the square matrix and test det ≠ 0.
8. Independence, Basis and Rank — One Summary Table
| Statement | Equivalent formulation |
|---|---|
| n vectors in Rⁿ are independent | The n × n matrix is non-singular (det ≠ 0); rank = n |
| They form a basis of Rⁿ | They are independent and span Rⁿ (for exactly n vectors, either property implies the other) |
| The set is dependent | Rank of the matrix of vectors < number of vectors |
| Dimension of the span | = rank of the matrix of vectors |
| Rⁿ has dimension n | Standard basis e₁, …, eₙ has n vectors |
9. Exam Points
- Define linear independence, span, basis and dimension for Rⁿ — 5 marks, almost certain.
- Show that n linearly independent vectors in Rⁿ form a basis of Rⁿ — 5-7 marks, very frequent.
- Prove that any set of more than n vectors in Rⁿ is linearly dependent — 5 marks.
- Test whether a given set of 3 vectors is a basis of R³ — 5 marks.
- Express a given vector as a linear combination of a given basis (find coordinates) — 5-7 marks, frequent.
- Reduce a dependent spanning set to a basis — 5 marks.
- State the standard basis of R³ and the dimension of Rⁿ — 3 marks.