Stokes'
1. Statement — Stokes' Theorem
Let be an oriented, piecewise smooth open surface bounded by a closed, piecewise smooth curve with orientation given by right-hand rule (fingers along , thumb along ). If has continuous first partials on an open region containing , then:
The line integral around (circulation) equals the flux of through any surface spanning . For in -plane, this reduces to Green's theorem.
2. Geometric Meaning
measures local rotation; Stokes says total swirl through equals circulation around its edge. If on , then for any bounding (conservative).
3. Working Steps (recipe)
- Choose spanning (often the planar disc bounded by is easiest).
- Compute .
- Find unit normal (right-hand rule decides sign) and (for , ).
- Evaluate .
If is given as intersection of two surfaces, the spanning surface is either.
4. Worked Examples
(a) F= -y i+ x j, C: circle x²+y²=a² in plane z=0, counter-clockwise when seen from +z.
∇×F=2k. Choose S = disc in plane z=0, n=k, (∇×F)·n=2 ⇒ ∬_{S}2 dS=2·πa²=2πa² ✓ matches line integral 2πa² from earlier.
(b) F= y i+ z j+ x k, C: intersection of sphere x²+y²+z²=9 and plane z=0?? Actually C is circle. Choose S = disc? Need compute: ∇×F= (-1+?) Compute: R_y -Q_z =0-1=-1 for i, P_z -R_x=0-1=-1 j, Q_x -P_y=0-1=-1 k ⇒ (-1,-1,-1); flux through disc n=k gives -1·area.
(c) Verify for hemisphere S: x²+y²+z²=a², z≥0 bounded by circle C in xy-plane: direct line integral ∮_{C} F·dr vs ∬_{S} curl F·n dS should match ⇒ often asked as verification problem (next topic).
(d) Need orientation: if C clockwise when seen from tip of n, sign flips.
(e) If F=∇φ, then curl zero ⇒ ∮=0 for any closed C that bounds a surface where curl continuous — re-proves conservative.
5. Relation to Green
Green's is Stokes in the plane: flat in , , .
6. Exam Points
- State Stokes' theorem — 3-5 marks, almost certain.
- Evaluate via for circle/hemisphere — 7 marks, very frequent.
- Verify for given — next topic's verification problems often use Stokes — 10 marks, very frequent (compulsory).
- Show if — 3 marks.