Integral Calculus (9hrs) · Engineering Mathematics - I

Evaluation of Triple integral by changing to Spherical Polar co-ordinates

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Evaluation of Triple integral by changing to Spherical Polar co-ordinates

1. Why Spherical

When VV is a ball, hemisphere, spherical shell, cone, or integrand involves x2+y2+z2=r2x²+y²+z² = r², spherical polar (r,θ,φ)(r,θ,φ) simplifies. Definitions (mathematical vs physics swapped — use the convention your notes use; here θθ = azimuth in xyxy, φφ = colatitude from zz):

x=rsinφcosθ,y=rsinφsinθ,z=rcosφ,r≥0,θ∈[0,2π),φ∈[0,π]x = r sinφ cosθ , y = r sinφ sinθ , z = r cosφ , r≥0, θ∈[0,2π), φ∈[0,π]

with r=√(x2+y2+z2)r = √(x²+y²+z²), x2+y2+z2=r2x²+y²+z² = r², and Jacobian (volume element):

dV=r2sinφdrdφdθdV = r² sinφ dr dφ dθ

If your text swaps θ↔φθ↔φ, the sinsin stays with the angle from zz; the r2r² factor remains.

2. Limits

  • Full ball x2+y2+z2≤a2x²+y²+z² ≤ a²: r0→a,φ0→π,θ0→2πr 0→a, φ 0→π, θ 0→2π.
  • Ball octant x≥0,y≥0,z≥0x≥0,y≥0,z≥0: θ0→π/2,φ0→π/2,r0→aθ 0→π/2, φ 0→π/2, r 0→a.
  • Hemisphere z≥0z≥0: φ0→π/2φ 0→π/2.
  • Between spheres a≤r≤ba≤r≤b: ra→br a→b.
  • Cone z=√(x2+y2)z = √(x²+y²) ⇒ φ=π/4φ = π/4 (since tanφ=√(x2+y2)/z=1tan φ = √(x²+y²)/z =1).

3. Worked Examples

(a) Volume of sphere radius a: V= ∫_{0}^{2π}∫_{0}^{π}∫_{0}^{a} r² sinφ dr dφ dθ = 4π a³/3 ✓

(b) ∭_{x²+y²+z²≤a²} (x²+y²+z²) dV = ∫_{0}^{2π}∫_{0}^{π}∫_{0}^{a} r²· r² sinφ dr dφ dθ = 4π·a⁵/5? Actually ∫ r⁴ dr = a⁵/5, angular integral 4π ⇒ 4π a⁵/5 ✓

(c) ∭_{hemisphere z≥0} z dV : = ∫_{0}^{2π}∫_{0}^{π/2}∫_{0}^{a} (r cosφ)·r² sinφ dr dφ dθ = 2π·(a⁴/4)·(1/2)·? Compute: ∫ cosφ sinφ dφ 0→π/2 =1/2, ∫ r³ dr =a⁴/4 ⇒ = π a⁴/4 ✓

(d) Mass of ball with density ρ = k r (proportional to distance from origin): Mass= ∭ k r dV = ∫∫∫ k r·r² sinφ =4π k a⁴/4? Actually ∫ k r³ dr =k a⁴/4 ×4π ⇒ π k a⁴ ✓

(e) I = ∫_{0}^{a}∫_{0}^{√(a²-x²)}∫_{0}^{√(a²-x²-y²)} (x²+y²+z²)^{3/2} dz dy dx (octant): convert ⇒ ∫_{0}^{π/2}∫_{0}^{π/2}∫_{0}^{a} r³·r² sinφ dr dφ dθ = (π/2)(1)·a⁶/6? Actually r³·r²= r⁵? Wait (r²)^{3/2}=r³, times Jacobian r² sinφ ⇒ r⁵ sinφ ⇒ ∫ r⁵= a⁶/6 × (π/2) ✓

4. Tips

  • Do not forget r2sinφr² sinφ — most errors drop it.
  • Keep θ,φθ, φ order consistent with dVdV you write.
  • For ∭octant∭_{octant}, θ,φθ,φ each 0→π/20→π/2.

5. Exam Points

  • Convert ∭Vf(x,y,z)dV∭_{V} f(x,y,z) dV over ball/cone to ∭f(r)r2sinφdrdφdθ∭ f(r) r² sinφ dr dφ dθ — 7 marks, very frequent.
  • Evaluate ∭(x2+y2+z2)∭ (x²+y²+z²), ∭z∭ z over sphere/hemisphere — 7 marks, frequent.
  • Volume via spherical — 5 marks, frequent.
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